2t-2+8=2(t-1)

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Solution for 2t-2+8=2(t-1) equation: 



2t-2+8=2(t-1)

We move all terms to the left:

2t-2+8-(2(t-1))=0

We add all the numbers together, and all the variables

2t-(2(t-1))+6=0



We calculate terms in parentheses: -(2(t-1)), so:

2(t-1)

We multiply parentheses

2t-2

Back to the equation:

-(2t-2)



We get rid of parentheses

2t-2t+2+6=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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