2t+5t-9=3(t-4)-5

Solution for 2t+5t-9=3(t-4)-5 equation:

2t+5t-9=3(t-4)-5

We move all terms to the left:

2t+5t-9-(3(t-4)-5)=0

We add all the numbers together, and all the variables

7t-(3(t-4)-5)-9=0


We calculate terms in parentheses: -(3(t-4)-5), so:

3(t-4)-5

We multiply parentheses

3t-12-5

We add all the numbers together, and all the variables

3t-17

Back to the equation:

-(3t-17)


We get rid of parentheses

7t-3t+17-9=0

We add all the numbers together, and all the variables

4t+8=0

We move all terms containing t to the left, all other terms to the right

4t=-8

t=-8/4

t=-2