2t+4/3+1)2t=1/4t-7/3

Solution for 2t+4/3+1)2t=1/4t-7/3 equation:

2t+4/3+1)2t=1/4t-7/3

We move all terms to the left:

2t+4/3+1)2t-(1/4t-7/3)=0


Domain of the equation: 4t!=0

t!=0/4

t!=0

t∈R


We add all the numbers together, and all the variables

2t+1)2t-(+1/4t+4/3-7/3)=0

We calculate fractions


2t+1)2t-(+()/108t^2+16t/108t^2+(-28t)/108t^2=0

We multiply all the terms by the denominator


2t*108t^2+12t-()*108t^2+16t+(-28t)+()=0

We add all the numbers together, and all the variables

28t+2t*108t^2-()*108t^2+(-28t)=0

Wy multiply elements

216t^3+28t-()*108t^2+(-28t)=0

We get rid of parentheses

216t^3+28t-()*108t^2-28t=0

We do not support etpression: t^3