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2t+10/t=12
We move all terms to the left:
2t+10/t-(12)=0
Domain of the equation: t!=0We multiply all the terms by the denominator
t∈R
2t*t-12*t+10=0
We add all the numbers together, and all the variables
-12t+2t*t+10=0
Wy multiply elements
2t^2-12t+10=0
a = 2; b = -12; c = +10;
Δ = b2-4ac
Δ = -122-4·2·10
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-8}{2*2}=\frac{4}{4} =1 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+8}{2*2}=\frac{20}{4} =5 $
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