2sin(4x-40)+3=4

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Solution for 2sin(4x-40)+3=4 equation:


Simplifying
2sin(4x + -40) + 3 = 4

Reorder the terms:
2ins(-40 + 4x) + 3 = 4
(-40 * 2ins + 4x * 2ins) + 3 = 4
(-80ins + 8insx) + 3 = 4

Reorder the terms:
3 + -80ins + 8insx = 4

Solving
3 + -80ins + 8insx = 4

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -80ins + -3 + 8insx = 4 + -3

Reorder the terms:
3 + -3 + -80ins + 8insx = 4 + -3

Combine like terms: 3 + -3 = 0
0 + -80ins + 8insx = 4 + -3
-80ins + 8insx = 4 + -3

Combine like terms: 4 + -3 = 1
-80ins + 8insx = 1

Reorder the terms:
-1 + -80ins + 8insx = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -80ins + 8insx = 0

The solution to this equation could not be determined.

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