2s-7=3(2s+1)

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Solution for 2s-7=3(2s+1) equation:



2s-7=3(2s+1)
We move all terms to the left:
2s-7-(3(2s+1))=0
We calculate terms in parentheses: -(3(2s+1)), so:
3(2s+1)
We multiply parentheses
6s+3
Back to the equation:
-(6s+3)
We get rid of parentheses
2s-6s-3-7=0
We add all the numbers together, and all the variables
-4s-10=0
We move all terms containing s to the left, all other terms to the right
-4s=10
s=10/-4
s=-2+1/2

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