2s-4=5(-4-2s)+1/2

Solution for 2s-4=5(-4-2s)+1/2 equation:

2s-4=5(-4-2s)+1/2

We move all terms to the left:

2s-4-(5(-4-2s)+1/2)=0

We add all the numbers together, and all the variables

2s-(5(-2s-4)+1/2)-4=0

We multiply all the terms by the denominator


2s*2)-(5(-2s-4)+1-4*2)=0

We add all the numbers together, and all the variables

2s*2)-(5(-2s-4)=0

Wy multiply elements

4s^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$s=\frac{-b}{2a}=\frac{0}{8}=0$