2r2-3=-3-2(2r-r2)

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Solution for 2r2-3=-3-2(2r-r2) equation: 



2r^2-3=-3-2(2r-r2)

We move all terms to the left:

2r^2-3-(-3-2(2r-r2))=0

We add all the numbers together, and all the variables

2r^2-(-3-2(+2r-1r^2))-3=0



We calculate terms in parentheses: -(-3-2(+2r-1r^2)), so:

-3-2(+2r-1r^2)

determiningTheFunctionDomain
-2(+2r-1r^2)-3

We multiply parentheses

2r^2-4r-3

Back to the equation:

-(2r^2-4r-3)



We get rid of parentheses

2r^2-2r^2+4r+3-3=0

We add all the numbers together, and all the variables

4r=0

r=0/4

r=0

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