2r-3(r+1)=6-2r

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Solution for 2r-3(r+1)=6-2r equation: 



2r-3(r+1)=6-2r

We move all terms to the left:

2r-3(r+1)-(6-2r)=0

We add all the numbers together, and all the variables

2r-3(r+1)-(-2r+6)=0

We multiply parentheses

2r-3r-(-2r+6)-3=0

We get rid of parentheses

2r-3r+2r-6-3=0

We add all the numbers together, and all the variables

r-9=0

We move all terms containing r to the left, all other terms to the right

r=9

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