2r-2+3(r-3)=2(r+5)

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Solution for 2r-2+3(r-3)=2(r+5) equation:


Simplifying
2r + -2 + 3(r + -3) = 2(r + 5)

Reorder the terms:
2r + -2 + 3(-3 + r) = 2(r + 5)
2r + -2 + (-3 * 3 + r * 3) = 2(r + 5)
2r + -2 + (-9 + 3r) = 2(r + 5)

Reorder the terms:
-2 + -9 + 2r + 3r = 2(r + 5)

Combine like terms: -2 + -9 = -11
-11 + 2r + 3r = 2(r + 5)

Combine like terms: 2r + 3r = 5r
-11 + 5r = 2(r + 5)

Reorder the terms:
-11 + 5r = 2(5 + r)
-11 + 5r = (5 * 2 + r * 2)
-11 + 5r = (10 + 2r)

Solving
-11 + 5r = 10 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
-11 + 5r + -2r = 10 + 2r + -2r

Combine like terms: 5r + -2r = 3r
-11 + 3r = 10 + 2r + -2r

Combine like terms: 2r + -2r = 0
-11 + 3r = 10 + 0
-11 + 3r = 10

Add '11' to each side of the equation.
-11 + 11 + 3r = 10 + 11

Combine like terms: -11 + 11 = 0
0 + 3r = 10 + 11
3r = 10 + 11

Combine like terms: 10 + 11 = 21
3r = 21

Divide each side by '3'.
r = 7

Simplifying
r = 7

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