2r+(2r+4)=2(3r+5)

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Solution for 2r+(2r+4)=2(3r+5) equation: 



2r+(2r+4)=2(3r+5)

We move all terms to the left:

2r+(2r+4)-(2(3r+5))=0

We get rid of parentheses

2r+2r-(2(3r+5))+4=0



We calculate terms in parentheses: -(2(3r+5)), so:

2(3r+5)

We multiply parentheses

6r+10

Back to the equation:

-(6r+10)



We add all the numbers together, and all the variables

4r-(6r+10)+4=0

We get rid of parentheses

4r-6r-10+4=0

We add all the numbers together, and all the variables

-2r-6=0

We move all terms containing r to the left, all other terms to the right

-2r=6

r=6/-2

r=-3

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