2q=(16)/(q)+q

Solution for 2q=(16)/(q)+q equation:

2q=(16)/(q)+q

We move all terms to the left:

2q-((16)/(q)+q)=0


Domain of the equation: q+q)!=0

q∈R


We add all the numbers together, and all the variables

2q-(+q+16/q)=0

We get rid of parentheses

2q-q-16/q=0

We multiply all the terms by the denominator


2q*q-q*q-16=0

Wy multiply elements

2q^2-1q^2-16=0

We add all the numbers together, and all the variables

q^2-16=0

a = 1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·1·(-16)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*1}=\frac{-8}{2}
=-4
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*1}=\frac{8}{2}
=4
$