2q+7-5q+8=3(5+6q)-12q

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Solution for 2q+7-5q+8=3(5+6q)-12q equation: 



2q+7-5q+8=3(5+6q)-12q

We move all terms to the left:

2q+7-5q+8-(3(5+6q)-12q)=0

We add all the numbers together, and all the variables

2q-5q-(3(6q+5)-12q)+7+8=0

We add all the numbers together, and all the variables

-3q-(3(6q+5)-12q)+15=0



We calculate terms in parentheses: -(3(6q+5)-12q), so:

3(6q+5)-12q

We add all the numbers together, and all the variables

-12q+3(6q+5)

We multiply parentheses

-12q+18q+15

We add all the numbers together, and all the variables

6q+15

Back to the equation:

-(6q+15)



We get rid of parentheses

-3q-6q-15+15=0

We add all the numbers together, and all the variables

-9q=0

q=0/-9

q=0

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