2q+10=7q/q=

Solution for 2q+10=7q/q= equation:

2q+10=7q/q=

We move all terms to the left:

2q+10-(7q/q)=0


Domain of the equation: q)!=0

q!=0/1

q!=0

q∈R


We add all the numbers together, and all the variables

2q-(+7q/q)+10=0

We get rid of parentheses

2q-7q/q+10=0

We multiply all the terms by the denominator


2q*q-7q+10*q=0

We add all the numbers together, and all the variables

3q+2q*q=0

Wy multiply elements

2q^2+3q=0

a = 2; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·2·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*2}=\frac{-6}{4}
=-1+1/2
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*2}=\frac{0}{4}
=0
$