2p-4(5-2p)=6(p-2)-16

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Solution for 2p-4(5-2p)=6(p-2)-16 equation: 



2p-4(5-2p)=6(p-2)-16

We move all terms to the left:

2p-4(5-2p)-(6(p-2)-16)=0

We add all the numbers together, and all the variables

2p-4(-2p+5)-(6(p-2)-16)=0

We multiply parentheses

2p+8p-(6(p-2)-16)-20=0



We calculate terms in parentheses: -(6(p-2)-16), so:

6(p-2)-16

We multiply parentheses

6p-12-16

We add all the numbers together, and all the variables

6p-28

Back to the equation:

-(6p-28)



We add all the numbers together, and all the variables

10p-(6p-28)-20=0

We get rid of parentheses

10p-6p+28-20=0

We add all the numbers together, and all the variables

4p+8=0

We move all terms containing p to the left, all other terms to the right

4p=-8

p=-8/4

p=-2

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