2p-2(6-3p)=3(p-4)-40

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Solution for 2p-2(6-3p)=3(p-4)-40 equation: 



2p-2(6-3p)=3(p-4)-40

We move all terms to the left:

2p-2(6-3p)-(3(p-4)-40)=0

We add all the numbers together, and all the variables

2p-2(-3p+6)-(3(p-4)-40)=0

We multiply parentheses

2p+6p-(3(p-4)-40)-12=0



We calculate terms in parentheses: -(3(p-4)-40), so:

3(p-4)-40

We multiply parentheses

3p-12-40

We add all the numbers together, and all the variables

3p-52

Back to the equation:

-(3p-52)



We add all the numbers together, and all the variables

8p-(3p-52)-12=0

We get rid of parentheses

8p-3p+52-12=0

We add all the numbers together, and all the variables

5p+40=0

We move all terms containing p to the left, all other terms to the right

5p=-40

p=-40/5

p=-8

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