2p-2(4-2p)=2(p-2)-32

Solution for 2p-2(4-2p)=2(p-2)-32 equation:

2p-2(4-2p)=2(p-2)-32

We move all terms to the left:

2p-2(4-2p)-(2(p-2)-32)=0

We add all the numbers together, and all the variables

2p-2(-2p+4)-(2(p-2)-32)=0

We multiply parentheses

2p+4p-(2(p-2)-32)-8=0


We calculate terms in parentheses: -(2(p-2)-32), so:

2(p-2)-32

We multiply parentheses

2p-4-32

We add all the numbers together, and all the variables

2p-36

Back to the equation:

-(2p-36)


We add all the numbers together, and all the variables

6p-(2p-36)-8=0

We get rid of parentheses

6p-2p+36-8=0

We add all the numbers together, and all the variables

4p+28=0

We move all terms containing p to the left, all other terms to the right

4p=-28

p=-28/4

p=-7