If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2n^2-4n-16=0
a = 2; b = -4; c = -16;
Δ = b2-4ac
Δ = -42-4·2·(-16)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-12}{2*2}=\frac{-8}{4} =-2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+12}{2*2}=\frac{16}{4} =4 $
| 4t-3=0,t= | | A+6=13a-18 | | P=16w+2 | | 0.5x-9=-4 | | 16t=116 | | .y-24=-7 | | -8.75x+14=-5.25x–3.5 | | -15x-30=-75 | | h/14+-133=-121 | | 15+23=x | | 8p=14p-72 | | (2x21)=180 | | 21+3x=−15 | | 37+30w=967 | | 2+x=68 | | 6. 8x=72 | | 130=v/7+107 | | 40=8x-9 | | 77=0.5(h+3)h | | 1+x=68 | | .-69=7v-6 | | 9(u+1)=99 | | 3x=4=1x=-6 | | x+2x-4=9x+2 | | n2+n-20=0 | | 2(r-65)=42 | | 14x9=3 | | 4(x-4);×=7 | | .4y-9=15 | | 15=⅓x+12 | | 3b-9=5b-75 | | 2(r-65=42 |