2n-4=2(n-2)

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Solution for 2n-4=2(n-2) equation:



2n-4=2(n-2)
We move all terms to the left:
2n-4-(2(n-2))=0
We calculate terms in parentheses: -(2(n-2)), so:
2(n-2)
We multiply parentheses
2n-4
Back to the equation:
-(2n-4)
We get rid of parentheses
2n-2n+4-4=0
We add all the numbers together, and all the variables
=0
n=0/1
n=0

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