2n-3(4n-5)=-6(n-3)-1

Solution for 2n-3(4n-5)=-6(n-3)-1 equation:

2n-3(4n-5)=-6(n-3)-1

We move all terms to the left:

2n-3(4n-5)-(-6(n-3)-1)=0

We multiply parentheses

2n-12n-(-6(n-3)-1)+15=0


We calculate terms in parentheses: -(-6(n-3)-1), so:

-6(n-3)-1

We multiply parentheses

-6n+18-1

We add all the numbers together, and all the variables

-6n+17

Back to the equation:

-(-6n+17)


We add all the numbers together, and all the variables

-10n-(-6n+17)+15=0

We get rid of parentheses

-10n+6n-17+15=0

We add all the numbers together, and all the variables

-4n-2=0

We move all terms containing n to the left, all other terms to the right

-4n=2

n=2/-4

n=-1/2