2n-3(1-3n)=41

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Solution for 2n-3(1-3n)=41 equation: 



2n-3(1-3n)=41

We move all terms to the left:

2n-3(1-3n)-(41)=0

We add all the numbers together, and all the variables

2n-3(-3n+1)-41=0

We multiply parentheses

2n+9n-3-41=0

We add all the numbers together, and all the variables

11n-44=0

We move all terms containing n to the left, all other terms to the right

11n=44

n=44/11

n=4

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