2n-15=1+4(n-5)

Solution for 2n-15=1+4(n-5) equation:

2n-15=1+4(n-5)

We move all terms to the left:

2n-15-(1+4(n-5))=0


We calculate terms in parentheses: -(1+4(n-5)), so:

1+4(n-5)

determiningTheFunctionDomain
4(n-5)+1

We multiply parentheses

4n-20+1

We add all the numbers together, and all the variables

4n-19

Back to the equation:

-(4n-19)


We get rid of parentheses

2n-4n+19-15=0

We add all the numbers together, and all the variables

-2n+4=0

We move all terms containing n to the left, all other terms to the right

-2n=-4

n=-4/-2

n=+2