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2n-11/5n=16
We move all terms to the left:
2n-11/5n-(16)=0
Domain of the equation: 5n!=0We multiply all the terms by the denominator
n!=0/5
n!=0
n∈R
2n*5n-16*5n-11=0
Wy multiply elements
10n^2-80n-11=0
a = 10; b = -80; c = -11;
Δ = b2-4ac
Δ = -802-4·10·(-11)
Δ = 6840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6840}=\sqrt{36*190}=\sqrt{36}*\sqrt{190}=6\sqrt{190}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-6\sqrt{190}}{2*10}=\frac{80-6\sqrt{190}}{20} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+6\sqrt{190}}{2*10}=\frac{80+6\sqrt{190}}{20} $
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