2n-1/3(36n+45)=-6(n-3)-1

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Solution for 2n-1/3(36n+45)=-6(n-3)-1 equation: 



2n-1/3(36n+45)=-6(n-3)-1

We move all terms to the left:

2n-1/3(36n+45)-(-6(n-3)-1)=0



Domain of the equation: 3(36n+45)!=0

n∈R



We multiply all the terms by the denominator


2n*3(36n+45)-((-6(n-3)-1))*3(36n+45)-1=0



We calculate terms in parentheses: -((-6(n-3)-1))*3(36n+45), so:

(-6(n-3)-1))*3(36n+45



Wy multiply elements

6n^2(3-((-6(n-3)-1))*3(36n+45)-1=0

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