2n+3(n+2)=2(n+4)+7

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Solution for 2n+3(n+2)=2(n+4)+7 equation: 



2n+3(n+2)=2(n+4)+7

We move all terms to the left:

2n+3(n+2)-(2(n+4)+7)=0

We multiply parentheses

2n+3n-(2(n+4)+7)+6=0



We calculate terms in parentheses: -(2(n+4)+7), so:

2(n+4)+7

We multiply parentheses

2n+8+7

We add all the numbers together, and all the variables

2n+15

Back to the equation:

-(2n+15)



We add all the numbers together, and all the variables

5n-(2n+15)+6=0

We get rid of parentheses

5n-2n-15+6=0

We add all the numbers together, and all the variables

3n-9=0

We move all terms containing n to the left, all other terms to the right

3n=9

n=9/3

n=3

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