2n+2n-3n-n+2n=2

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Solution for 2n+2n-3n-n+2n=2 equation: 



2n+2n-3n-n+2n=2

We move all terms to the left:

2n+2n-3n-n+2n-(2)=0

We add all the numbers together, and all the variables

2n-2=0

We move all terms containing n to the left, all other terms to the right

2n=2

n=2/2

n=1

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