2n+(3n+1)+2(3n+2)=147

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Solution for 2n+(3n+1)+2(3n+2)=147 equation: 



2n+(3n+1)+2(3n+2)=147

We move all terms to the left:

2n+(3n+1)+2(3n+2)-(147)=0

We multiply parentheses

2n+(3n+1)+6n+4-147=0

We get rid of parentheses

2n+3n+6n+1+4-147=0

We add all the numbers together, and all the variables

11n-142=0

We move all terms containing n to the left, all other terms to the right

11n=142

n=142/11

n=12+10/11

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