2n+(2n+2)+(2n+4)=48

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Solution for 2n+(2n+2)+(2n+4)=48 equation: 



2n+(2n+2)+(2n+4)=48

We move all terms to the left:

2n+(2n+2)+(2n+4)-(48)=0

We get rid of parentheses

2n+2n+2n+2+4-48=0

We add all the numbers together, and all the variables

6n-42=0

We move all terms containing n to the left, all other terms to the right

6n=42

n=42/6

n=7

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