2n(33-n)=0

Solution for 2n(33-n)=0 equation:

2n(33-n)=0

We add all the numbers together, and all the variables

2n(-1n+33)=0

We multiply parentheses

-2n^2+66n=0

a = -2; b = 66; c = 0;
Δ = b2-4ac
Δ = 662-4·(-2)·0
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-66}{2*-2}=\frac{-132}{-4}
=+33
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+66}{2*-2}=\frac{0}{-4}
=0
$