2n^2+2n/10n^2+4n

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Solution for 2n^2+2n/10n^2+4n equation: 


n in (-oo:+oo)

((2*n)/10)*n^2+2*n^2+4*n = 0

1/5*n^3+2*n^2+4*n = 0

n*(1/5*n^2+2*n+4) = 0

1/5*n^2+2*n+4 = 0

DELTA = 2^2-(1/5*4*4)

DELTA = 4/5

DELTA > 0

n = ((4/5)^(1/2)-2)/(1/5*2) or n = (-(4/5)^(1/2)-2)/(1/5*2)

n = 5/2*((4/5)^(1/2)-2) or n = -5/2*((4/5)^(1/2)+2)

n = 0

n = 0

n in { -5/2*((4/5)^(1/2)+2), 5/2*((4/5)^(1/2)-2), 0 }

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