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2m=2/m
We move all terms to the left:
2m-(2/m)=0
Domain of the equation: m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
2m-(+2/m)=0
We get rid of parentheses
2m-2/m=0
We multiply all the terms by the denominator
2m*m-2=0
Wy multiply elements
2m^2-2=0
a = 2; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·2·(-2)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*2}=\frac{-4}{4} =-1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*2}=\frac{4}{4} =1 $
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