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2m^2+11m=15.
We move all terms to the left:
2m^2+11m-(15.)=0
We add all the numbers together, and all the variables
2m^2+11m-15=0
a = 2; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·2·(-15)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{241}}{2*2}=\frac{-11-\sqrt{241}}{4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{241}}{2*2}=\frac{-11+\sqrt{241}}{4} $
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