2m/5=10/m

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Solution for 2m/5=10/m equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(2*m)/5 = 10/m // - 10/m

(2*m)/5-(10/m) = 0

(2*m)/5-10*m^-1 = 0

2/5*m^1-10*m^-1 = 0

(2/5*m^2-10*m^0)/(m^1) = 0 // * m^2

m^1*(2/5*m^2-10*m^0) = 0

m^1

(2/5)*m^2-10 = 0

(2/5)*m^2-10 = 0

DELTA = 0^2-(-10*4*(2/5))

DELTA = 16

DELTA > 0

m = (16^(1/2)+0)/(2*(2/5)) or m = (0-16^(1/2))/(2*(2/5))

m = 5 or m = -5

m in { -5, 5} 

m in { -5, 5 }

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