2m-3m(2m-4)=-2(3m-8)+2

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Solution for 2m-3m(2m-4)=-2(3m-8)+2 equation: 



2m-3m(2m-4)=-2(3m-8)+2

We move all terms to the left:

2m-3m(2m-4)-(-2(3m-8)+2)=0

We multiply parentheses

-6m^2+2m+12m-(-2(3m-8)+2)=0



We calculate terms in parentheses: -(-2(3m-8)+2), so:

-2(3m-8)+2

We multiply parentheses

-6m+16+2

We add all the numbers together, and all the variables

-6m+18

Back to the equation:

-(-6m+18)



We add all the numbers together, and all the variables

-6m^2+14m-(-6m+18)=0

We get rid of parentheses

-6m^2+14m+6m-18=0

We add all the numbers together, and all the variables

-6m^2+20m-18=0

a = -6; b = 20; c = -18;
Δ = b2-4ac
Δ = 202-4·(-6)·(-18)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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