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2m-3=6/m
We move all terms to the left:
2m-3-(6/m)=0
Domain of the equation: m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
2m-(+6/m)-3=0
We get rid of parentheses
2m-6/m-3=0
We multiply all the terms by the denominator
2m*m-3*m-6=0
We add all the numbers together, and all the variables
-3m+2m*m-6=0
Wy multiply elements
2m^2-3m-6=0
a = 2; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·2·(-6)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*2}=\frac{3-\sqrt{57}}{4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*2}=\frac{3+\sqrt{57}}{4} $
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