2m-20=0,1/2m=

Solution for 2m-20=0,1/2m= equation:

2m-20=0.1/2m=

We move all terms to the left:

2m-20-(0.1/2m)=0


Domain of the equation: 2m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2m-(+0.1/2m)-20=0

We get rid of parentheses

2m-0.1/2m-20=0

We multiply all the terms by the denominator


2m*2m-20*2m-0.1=0

Wy multiply elements

4m^2-40m-0.1=0

a = 4; b = -40; c = -0.1;
Δ = b2-4ac
Δ = -402-4·4·(-0.1)
Δ = 1601.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-\sqrt{1601.6}}{2*4}=\frac{40-\sqrt{1601.6}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+\sqrt{1601.6}}{2*4}=\frac{40+\sqrt{1601.6}}{8}
$