2m-(7m+12)=2(m-3)

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Solution for 2m-(7m+12)=2(m-3) equation: 



2m-(7m+12)=2(m-3)

We move all terms to the left:

2m-(7m+12)-(2(m-3))=0

We get rid of parentheses

2m-7m-(2(m-3))-12=0



We calculate terms in parentheses: -(2(m-3)), so:

2(m-3)

We multiply parentheses

2m-6

Back to the equation:

-(2m-6)



We add all the numbers together, and all the variables

-5m-(2m-6)-12=0

We get rid of parentheses

-5m-2m+6-12=0

We add all the numbers together, and all the variables

-7m-6=0

We move all terms containing m to the left, all other terms to the right

-7m=6

m=6/-7

m=-6/7

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