2m-(6m-9)+(3m-2)=4-(7m-8)

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Solution for 2m-(6m-9)+(3m-2)=4-(7m-8) equation: 



2m-(6m-9)+(3m-2)=4-(7m-8)

We move all terms to the left:

2m-(6m-9)+(3m-2)-(4-(7m-8))=0

We get rid of parentheses

2m-6m+3m-(4-(7m-8))+9-2=0



We calculate terms in parentheses: -(4-(7m-8)), so:

4-(7m-8)

determiningTheFunctionDomain
-(7m-8)+4

We get rid of parentheses

-7m+8+4

We add all the numbers together, and all the variables

-7m+12

Back to the equation:

-(-7m+12)



We add all the numbers together, and all the variables

-1m-(-7m+12)+7=0

We get rid of parentheses

-1m+7m-12+7=0

We add all the numbers together, and all the variables

6m-5=0

We move all terms containing m to the left, all other terms to the right

6m=5

m=5/6

m=5/6

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