2m+6=10/7(m=14)

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Solution for 2m+6=10/7(m=14) equation: 



2m+6=10/7(m=14)

We move all terms to the left:

2m+6-(10/7(m)=0



Domain of the equation: 7m+6!=0

We move all terms containing m to the left, all other terms to the right

7m!=-6

m!=-6/7

m!=-6/7

m∈R



We multiply all the terms by the denominator


2m*7m+6-(10=0

We add all the numbers together, and all the variables

2m*7m=0

Wy multiply elements

14m^2=0

a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{28}=0$

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