2m+4m(m+3)=30

Solution for 2m+4m(m+3)=30 equation:

2m+4m(m+3)=30

We move all terms to the left:

2m+4m(m+3)-(30)=0

We multiply parentheses

4m^2+2m+12m-30=0

We add all the numbers together, and all the variables

4m^2+14m-30=0

a = 4; b = 14; c = -30;
Δ = b2-4ac
Δ = 142-4·4·(-30)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*4}=\frac{-40}{8}
=-5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*4}=\frac{12}{8}
=1+1/2
$