2m+4(-3+m)=7m+-42m+(-3*4+m*4)=7m+-42m+(-12+4m)=7m+-4

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Solution for 2m+4(-3+m)=7m+-42m+(-3*4+m*4)=7m+-42m+(-12+4m)=7m+-4 equation: 



2m+4(-3+m)=7m+-42m+(-3*4+m*4)=7m+-42m+(-12+4m)=7m+-4

We move all terms to the left:

2m+4(-3+m)-(7m+-42m+(-3*4+m*4))=0

We add all the numbers together, and all the variables

2m+4(m-3)-(7m+-42m+(m*4-12))=0

We use the square of the difference formula

2m+4(m-3)-(7m-42m+(m*4-12))=0

We multiply parentheses

2m+4m-(7m-42m+(m*4-12))-12=0



We calculate terms in parentheses: -(7m-42m+(m*4-12)), so:

7m-42m+(m*4-12)

We add all the numbers together, and all the variables

-35m+(m*4-12)

We get rid of parentheses

-35m+m*4-12

Wy multiply elements

-35m+4m-12

We add all the numbers together, and all the variables

-31m-12

Back to the equation:

-(-31m-12)



We add all the numbers together, and all the variables

6m-(-31m-12)-12=0

We get rid of parentheses

6m+31m+12-12=0

We add all the numbers together, and all the variables

37m=0

m=0/37

m=0

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