2m+2(m+2)=20-(2m-5)

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Solution for 2m+2(m+2)=20-(2m-5) equation: 



2m+2(m+2)=20-(2m-5)

We move all terms to the left:

2m+2(m+2)-(20-(2m-5))=0

We multiply parentheses

2m+2m-(20-(2m-5))+4=0



We calculate terms in parentheses: -(20-(2m-5)), so:

20-(2m-5)

determiningTheFunctionDomain
-(2m-5)+20

We get rid of parentheses

-2m+5+20

We add all the numbers together, and all the variables

-2m+25

Back to the equation:

-(-2m+25)



We add all the numbers together, and all the variables

4m-(-2m+25)+4=0

We get rid of parentheses

4m+2m-25+4=0

We add all the numbers together, and all the variables

6m-21=0

We move all terms containing m to the left, all other terms to the right

6m=21

m=21/6

m=3+1/2

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