2m+11m=8(m-4)-9(12+m)

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Solution for 2m+11m=8(m-4)-9(12+m) equation: 



2m+11m=8(m-4)-9(12+m)

We move all terms to the left:

2m+11m-(8(m-4)-9(12+m))=0

We add all the numbers together, and all the variables

2m+11m-(8(m-4)-9(m+12))=0

We add all the numbers together, and all the variables

13m-(8(m-4)-9(m+12))=0



We calculate terms in parentheses: -(8(m-4)-9(m+12)), so:

8(m-4)-9(m+12)

We multiply parentheses

8m-9m-32-108

We add all the numbers together, and all the variables

-1m-140

Back to the equation:

-(-1m-140)



We get rid of parentheses

13m+1m+140=0

We add all the numbers together, and all the variables

14m+140=0

We move all terms containing m to the left, all other terms to the right

14m=-140

m=-140/14

m=-10

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