2m+1+m=4(m-2)=7

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Solution for 2m+1+m=4(m-2)=7 equation: 



2m+1+m=4(m-2)=7

We move all terms to the left:

2m+1+m-(4(m-2))=0

We add all the numbers together, and all the variables

3m-(4(m-2))+1=0



We calculate terms in parentheses: -(4(m-2)), so:

4(m-2)

We multiply parentheses

4m-8

Back to the equation:

-(4m-8)



We get rid of parentheses

3m-4m+8+1=0

We add all the numbers together, and all the variables

-1m+9=0

We move all terms containing m to the left, all other terms to the right

-m=-9

m=-9/-1

m=+9

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