2m(m-3)=10m

Solution for 2m(m-3)=10m equation:

2m(m-3)=10m

We move all terms to the left:

2m(m-3)-(10m)=0

We add all the numbers together, and all the variables

-10m+2m(m-3)=0

We multiply parentheses

2m^2-10m-6m=0

We add all the numbers together, and all the variables

2m^2-16m=0

a = 2; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·2·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*2}=\frac{0}{4}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*2}=\frac{32}{4}
=8
$