2m(3m+2)+(3m+2)=0

Solution for 2m(3m+2)+(3m+2)=0 equation:

2m(3m+2)+(3m+2)=0

We multiply parentheses

6m^2+4m+(3m+2)=0

We get rid of parentheses

6m^2+4m+3m+2=0

We add all the numbers together, and all the variables

6m^2+7m+2=0

a = 6; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·6·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*6}=\frac{-8}{12}
=-2/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*6}=\frac{-6}{12}
=-1/2
$