2log(4)(x+1)+log(4)(x-2)=2

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Solution for 2log(4)(x+1)+log(4)(x-2)=2 equation:


Simplifying
2log(4)(x + 1) + log(4)(x + -2) = 2

Reorder the terms:
2glo * 4(1 + x) + log(4)(x + -2) = 2

Reorder the terms for easier multiplication:
2 * 4glo(1 + x) + log(4)(x + -2) = 2

Multiply 2 * 4
8glo(1 + x) + log(4)(x + -2) = 2
(1 * 8glo + x * 8glo) + log(4)(x + -2) = 2
(8glo + 8glox) + log(4)(x + -2) = 2

Reorder the terms:
8glo + 8glox + glo * 4(-2 + x) = 2

Reorder the terms for easier multiplication:
8glo + 8glox + 4glo(-2 + x) = 2
8glo + 8glox + (-2 * 4glo + x * 4glo) = 2
8glo + 8glox + (-8glo + 4glox) = 2

Reorder the terms:
8glo + -8glo + 8glox + 4glox = 2

Combine like terms: 8glo + -8glo = 0
0 + 8glox + 4glox = 2
8glox + 4glox = 2

Combine like terms: 8glox + 4glox = 12glox
12glox = 2

Solving
12glox = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '12lox'.
g = 0.1666666667l-1o-1x-1

Simplifying
g = 0.1666666667l-1o-1x-1

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