2k=)3-7k/5

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Solution for 2k=)3-7k/5 equation: 



2k=)3-7k/5

We move all terms to the left:

2k-()3-7k/5)=0

We multiply all the terms by the denominator


2k*5)-()3-7k=0

Wy multiply elements

10k^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{20}=0$

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