2k/k+2+2/k=5

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Solution for 2k/k+2+2/k=5 equation: 



2k/k+2+2/k=5

We move all terms to the left:

2k/k+2+2/k-(5)=0



Domain of the equation: k!=0

k∈R



We add all the numbers together, and all the variables

2k/k+2/k-3=0

We multiply all the terms by the denominator


2k-3*k+2=0

We add all the numbers together, and all the variables

-1k+2=0

We move all terms containing k to the left, all other terms to the right

-k=-2

k=-2/-1

k=+2

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