2k-6+3-(k+10)=11

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Solution for 2k-6+3-(k+10)=11 equation: 



2k-6+3-(k+10)=11

We move all terms to the left:

2k-6+3-(k+10)-(11)=0

We add all the numbers together, and all the variables

2k-(k+10)-14=0

We get rid of parentheses

2k-k-10-14=0

We add all the numbers together, and all the variables

k-24=0

We move all terms containing k to the left, all other terms to the right

k=24

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